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NCERT Solutions for Class 12 Maths Chapter 7 – Integrals Exercise 7.3
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Chapter 7 – Integrals Exercise 7.3
1.

Flashcard for Question 1
Short Formula Recall:
sin²θ = (1 − cos 2θ) / 2
Quick Tip:
Use the half-angle identity to simplify before integrating.
Common Mistake:
Trying to integrate sin² directly without using the identity.
Exam Insight:
A standard integral simplification problem, commonly appearing in the integration-by-identities section.

2.

Flashcard for Question 2
Short Formula Recall:
sin A cos B = ½[sin(A + B) + sin(A − B)]
Quick Tip:
Apply the product-to-sum identity before integrating.
Common Mistake:
Directly trying to integrate the product without converting to a sum.
Exam Insight:
Classic example from trigonometric integration identities — often worth 2 marks in board exams.

3.

Flashcard for Question 3
Short Formula Recall:
cos A cos B = ½[cos(A + B) + cos(A − B)]
Quick Tip:
Reduce the product step-by-step using product-to-sum formulas until only single cosine terms remain for easy integration.
Common Mistake:
Skipping intermediate steps in product-to-sum conversion and making sign errors in angles.
Exam Insight:
A slightly tricky integration identity problem – good practice for multi-angle product simplifications.


4.

Flashcard for Question 4
Short Formula Recall:
sin³θ = sinθ (1 − cos²θ)
Quick Tip:
Split sin³ into sinθ(1 − cos²θ) and use u-substitution with u = cos(2x + 1).
Common Mistake:
Forgetting the chain rule factor when substituting, leading to a missing coefficient in the final answer.
Exam Insight:
Common example for testing odd-power sine integration and substitution skills.

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8.

Flashcard for Question 8
Short Formula Recall:
1 − cos x = 2 sin²(x/2), 1 + cos x = 2 cos²(x/2) ⇒ (1 − cos x)/(1 + cos x) = tan²(x/2)
Quick Tip:
Convert to half-angle form and use tan²θ = sec²θ − 1 to integrate easily.
Common Mistake:
Forgetting to apply the half-angle substitution correctly or missing the factor from dx when substituting u = x/2.
Exam Insight:
A standard trigonometric identity simplification before integration — shows up often in board exam practice papers.

9.

Flashcard for Question 9
Short Formula Recall:
1 + cos x = 2 cos²(x/2), cos x = 1 − 2 sin²(x/2)
Quick Tip:
Divide numerator and denominator by cos²(x/2) to simplify, then integrate using standard sec² and tan formulas.
Common Mistake:
Trying direct substitution without simplifying – leads to messy algebra.


10.

Flashcard for Question 10
Short Formula Recall:
sin²x = (1 − cos 2x)/2 ⇒ sin⁴x = [(1 − cos 2x)/2]²
Quick Tip:
Use the power-reduction identity twice to convert to a sum of cosines for easy integration.
Common Mistake:
Forgetting to square the (1/2) factor when expanding sin²x.

11.

Flashcard for Question 11
Quick Tip:
Use the power-reduction identity two times, then integrate each term independently, being careful to include the inner derivative of 2x.
Common Mistake:
Forgetting the chain rule factor (1/2) when integrating functions of 2x, 4x, etc.
Exam Insight:
A straightforward application of multiple-angle identities — worth 2–3 marks if done neatly

12.

Flashcard for Question 12
Quick Tip:
Cancel the (1 + cos x) term, leaving 1 − cos x, which integrates easily.
Common Mistake:
Forgetting to simplify before integrating — trying direct integration makes it unnecessarily hard.
Exam Insight:
A classic simplification-before-integration problem — often appears in short-answer sections.

13.

Flashcard for Question 13
Short Formula Recall:
cosA − cosB = −2 sin((A + B)/2) sin((A − B)/2);
sin2θ = 2 sinθ cosθ;
Quick Tip:
Use sum-to-product to simplify the fraction first — it reduces to a simple sum of cosines.
Common Mistake:
Skipping the cancellation step after converting to product form and making algebraic sign errors.
Exam Insight:
A neat 2–3 mark question: simplify first (reduces to elementary integrals) rather than attempting direct integration.


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17.

Flashcard for Question 17
Quick Tip:
Split the fraction: (sin³+cos³)/(sin² cos²) = sin/cos² + cos/sin² and match each term to a known derivative.
Common Mistake:
Not splitting the integrand or mishandling the sign for the csc derivative (cos/sin² = −(d/dx)csc x).
Exam Insight:
Recognising derivatives of sec and csc gives a one-step integral – typical 1–2 mark question if simplified neatly.

18.

Flashcard for Question 18
Quick Tip:
Substitute cos 2x and notice cancellation with 1-2 sin²x — the numerator becomes 1.
Common Mistake:
Expanding tan²x too early instead of spotting that the numerator simplifies directly.
Exam Insight:
A quick simplification turns the problem into ∫ sec²x dx, which is a one-step standard integral.

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21.

Flashcard for Question 21
Short Formula Recall:
sin⁻¹(cos x) = π/2 − x, for x ∈ [0, π]
Quick Tip:
Replace sin⁻¹(cos x) with its equivalent linear form to turn the integral into a basic polynomial integration.
Common Mistake:
Forgetting the principal value range of sin⁻¹, leading to wrong simplification outside [0, π].


22.

Flashcard for Question 22
Exam Insight:
This is a standard trick-question – simplify first using sum-to-product then use the tangent half-angle; it’s worth 3-4 marks if shown neatly.


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Download Exercise 7.3 NCERT Solutions PDF
You can download the PDF from the link below for offline study
Class 12 Maths Chapter 7 – Integrals: All Exercises
| Exercise | Link |
|---|---|
| Exercise 7.1 | View Solutions |
| Exercise 7.2 | View Solutions |
| Exercise 7.4 | View Solutions |
| Exercise 7.5 | View Solutions |
| Exercise 7.6 | View Solutions |
| Exercise 7.7 | View Solutions |
| Exercise 7.8 | View Solutions |
| Exercise 7.9 | View Solutions |
| Exercise 7.10 | View Solutions |
| Miscellaneous Exercise | View Solutions |
Class 12 Integrals- Exercise 7.3 Overview
One of the most crucial methods in integration—integration by parts—is introduced in Exercise 7.3 This is usually the secret if you have ever looked at an integral and wondered, “How on earth do I solve this?” It’s all about dissecting difficult ideas into sensible chunks; once you know the rule, using it is really fulfilling.
Integrals Class 12 NCERT Solutions Exercise 7.3 will teach you how to integrate functions that are products of two different kinds—such as algebraic function multiplied by a trigonometric or logarithmic one. The ILATE rule, a basic guidance to determine the sequence of operations using this approach, can also help you to get at ease.
This practice is a popular in both board exam questions and competitive exams and exactly corresponds with the 2025 revised NCERT Class 12 Maths syllabus. Some students find the setup difficult; once you break the pattern, it comes naturally.
Working through Chapter 7 Class 12 NCERT Solutions Exercise 7.3 helps you to feel confident in handling challenging tasks. More significantly, it gets you ready for real-world problem-solving scenarios where several functions interact—such as in economics, physics, and engineering.
FAQs – Integrals Class 12 Exercise 7.3 NCERT
This approach integrates the output of two functions. You divide it depending on a particular rule (ILATE) instead of solving it straight and work methodically.
Inverse trigonometric, logarithmic, algebraic, trigonometric, and exponential stands as ILATE. Applying integration by parts helps choose which function to differentiate from and which one to merge.
It largely results from the arrangement—selecting the appropriate component to differentiate or combine. Once you answer a few questions, though, you will find patterns more readily.
Sure, absolutely It appears in several disciplines, most notably engineering and physics (where motion problems are solved). Integrals Class 12 NCERT Solutions Exercise 7.3 develops fundamental problem-solving skills, not only a textbook chapter