NCERT Solutions for Class 10 Science Chapter 9 – Light – Reflection and Refraction

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Chapter 9 – Light – Reflection and Refraction

Intext Questions with Solutions of Class 10 Science Chapter 9 – Light – Reflection and Refraction

1.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ1: Principal focus concave mirror

Ans: Light rays parallel to the principal axis converge at a location on the principal axis following reflection from the concave mirror.
The convergence point along the principal axis of a concave mirror is referred to as the principal focus of the concave mirror.

2.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ2: Radius curvature 20cm focal length calculation

Ans:

Focal length formula: f = 1/2 × R = 1/2 × 20cm = 10cm showing radius curvature relationship with focal length

3.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ3: Mirror giving erect enlarged image

Ans: Concave mirror.

4.

NCERT Class 10 Ch-9 Light Q4: Convex mirror rear-view vehicles

Ans: In cars and other vehicles, a convex mirror is the ideal rearview mirror because it provides a larger field of view, allowing the driver to see most of the traffic behind him. Convex mirrors always create an erect, virtual, and diminished image of the item placed in front of them.

5.

NCERT Class 10 Ch-9 Light Q5: Convex mirror focal length radius 32cm - f=R/2 equals 16cm calculation with sign convention

Ans:

Convex mirror focal length: R=+32cm, f=R/2=+16cm calculation positive sign convention for convex mirror shown

6.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ6: Concave mirror 3x magnification object 10cm

Ans: The magnifying effect of a spherical mirror:

Magnification formula: m=h1/h0=-v/u, 3x magnification object -10cm gives image -30cm inverted real image distance calculation

As a result, the negative sign shows that, at a distance of 30 cm, an inverted picture forms in front of the specified concave mirror.

7.

NCERT Class 10 Ch-9 Light Q7: Light air to water refraction - bends toward normal rarer to denser medium transition

Ans: When a light ray transitions from a rarer media to a denser medium, it refracts towards the normal line.
The light ray refracts towards the normal as it transitions from a rarer media (air) to a denser medium (water).

8.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ8: Light speed glass refractive index 1.50

Ans: Refractive index of a medium (nm) = Speed of light in vacuum/Speed of light in the medium

Speed of light in vacuum (c) = 3 × 108 m/s

Refractive index of glass (ng) = 1.50

Speed of light in the glass (v) = Speed of light in vacuum/ Refractive index of glass

= c/ng

=3 × 108/1.50 = 2x 108 ms-1.

9.

NCERT Class 10 Ch-9 Light Q9: Highest lowest optical density table 9.3
Refractive index table: materials air 1.0003 to diamond 2.42, kerosene 1.44 turpentine 1.47 water 1.33 comparison shown

Ans: According to table 9.3, diamond has the largest optical density since it has the highest refractive index (= 2.42).
Air has the lowest optical density because it has the lowest refractive index (1.0003).

10.

NCERT Class 10 Ch-9 Light Q10: Light travels fastest kerosene turpentine water - water lowest refractive index 1.33

Ans: Kerosene has n = 1.44.
n = 1.47 for turpentine
n = 1.33 for water
Light moves more quickly through water than through kerosene and turpentine oil because it has the lowest refractive index.

11.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ11: Diamond refractive index 2.42 meaning

Ans: Since a diamond has a refractive index of 2.42, light traveling through it will travel at a speed that is 2.42 slower than it would in the atmosphere.

Stated differently, light travels 1/2.42 times faster in a diamond than it does in a vacuum.

12.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ12: One dioptre power definition -

Ans: The dioptre is the SI unit of lens power, represented by the letter D. One dioptre is defined as the optical power of a lens with a focal length of one metre.

13.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ13: Convex lens needle image 50cm equal size

Ans:

Lens formula: 1/f=1/v-1/u, v=50cm u=-50cm f=25cm power P=1/f=+4D converging lens calculation steps shown

14.

NCERT Class 10 Ch-9 Light – Reflection and RefractionQ14: Concave lens focal length 2m power

Ans:

Concave lens power: f=-2m, P=1/f=1/(-2)=-0.5D negative power indicates diverging lens nature formula shown

Exercise Questions with Solutions of Class 10 Science Chapter 9 – Light – Reflection and Refraction

1.

NCERT Class 10 Ch-9 Light – Reflection and RefractionEx-Q1: MCQ material cannot make lens

Ans: (d) Clay

2.

NCERT Class 10 Ch-9 Light – Reflection and RefractionEx-Q2: MCQ concave mirror virtual erect enlarged

Ans: (d) Between the pole of the mirror and its principal focus.

3.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q3: MCQ convex lens real image same size

Ans: (b) At twice the focal length.

4.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q4: MCQ focal length -15cm mirror lens

Ans: (a) Both concave

5.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q5: MCQ mirror always erect image

Ans: (d) Either plane or convex.

6.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q6: MCQ reading small dictionary letters

Ans: (c) A convex lens of focal length 5 cm.

7.

NCERT Class 10 Ch-9 Light Ex-Q7: Concave mirror 15cm erect image

Ans: When an object is positioned between the concave mirror’s focus F and pole P, or between 0 and 15 cm from the mirror, it produces an erect picture. The resulting image will be larger than the actual thing, upright, and imaginary.

Concave mirror ray diagram: object between pole P and focus F produces virtual erect enlarged image behind mirror shown

8.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q8: Mirror types car headlights rearview solar furnace

Ans:

  1. Concave Mirror: When positioned at their principal focus, concave mirrors can generate a strong parallel beam of light.
  2. Due to its widest field of view, the Convex Mirror is the best option.
  3. Concave Mirror: Due to its ability to concentrate the sun’s parallel beams at a primary point.

9.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q9: Half-covered convex lens complete image

Ans: A convex lens produces a complete image of an item, even when one half is obscured by black paper. This can be elucidated by examining the following two scenarios.

Scenario I: When the superior portion of the lens is obscured
A ray of light originating from the item will be refracted by the inferior portion of the lens. The rays converge on the other side of the lens to create the image of the specified object, as illustrated in the subsequent figure.

Half-covered convex lens upper part blocked: light rays from lower portion refract converge form complete image other side

Scenario II: When the inferior part of the lens is obscured . A ray of light originating from the item is refracted by the upper portion of the lens. The rays converge on the other side of the lens to create the image of the specified object, as illustrated in the accompanying figure.

Half-covered convex lens lower part blocked: light rays from upper portion refract converge form complete image demonstration

10.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q10: Object 5cm 25cm converging lens 10cm

Ans:

Lens formula complete: 1/v-1/u=1/f with u=-25cm f=10cm gives v=16.66cm, magnification h1=-3.3cm calculations detailed
Converging lens ray diagram: object 25cm focal 10cm rays converge 16.7cm behind lens inverted diminished image formation

11.

NCERT Class 10 Ch-9 Light Ex-Q11: Concave lens focal 15cm image 10cm

Ans:

Concave lens calculation: f=-15cm v=-10cm using 1/u=1/v-1/f gives u=-30cm object distance formula solution steps

12.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q12: Convex mirror object 10cm focal 15cm

Ans:

Mirror formula: 1/v=1/f-1/u with f=+15cm u=-10cm gives v=6cm, magnification m=0.6 virtual erect image calculation

13.

NCERT Class 10 Ch-9 Light Ex-Q13: Plane mirror magnification +1 meaning

Ans:

Magnification is defined as, 

Given that m = +1, it follows that h’ = h and v = -u.

  • The value of m = 1 signifies that the size of the image is identical to that of the object.
  • The positive sign of m indicates the formation of an erect image.
  • The differing signs of ν and u signify that the image is located on the opposite side of the mirror relative to the object’s position, indicating that the image is formed behind the mirror and is therefore virtual.

14.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q14: Object 5cm convex mirror radius 30cm

Ans:

Concave lens power: f=-2m, P=1/f=1/(-2)=-0.5D negative power indicates diverging lens nature formula shown

15.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q15: Object 7cm 27cm concave mirror 18cm

Ans:

Concave mirror formula: f=-18cm u=-27cm gives v=-54cm screen position, image size h'=-14cm real inverted enlarged

16.

NCERT Class 10 Ch-9 Light – Reflection and Refraction Ex-Q16: Lens power -2.0D focal length

Ans:

Power focal length relation: P=-2.0D gives f=-0.5m concave, P=+1.5D gives f=+66.67cm convex lens calculations

17.

NCERT Class 10 Ch-9 Light Ex-Q17: Corrective lens power +1.5D focal length

Ans:

Related Study Resources of Chapter 9 – Light – Reflection and Refraction

Students can use the links below to get extra study materials for Class 10 Science Chapter 9: Light – Reflection and Refraction.

Sl No.Related Links
1Class 10 Science Chapter 9 Light – Reflection and Refraction – Important Questions
2Class 10 Science Chapter 9 NCERT Textbook

Download Light – Reflection and Refraction NCERT Solutions PDF

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Class 10 Science Chapter 9 Overview

Class 10 Science has some of the most conceptually dense chapters, including Light: Reflection and Refraction. It shows kids how light acts when it hits surfaces or goes through different materials. Our Light – Reflection and Refraction NCERT Solutions help students comprehend how light rays behave, mirror and lens formulas, and real-world examples including how the human eye and optical instruments work.

It is frequently difficult for students to apply mathematics such as the mirror and lens equations, remember sign standards, or appropriately create ray diagrams. In order to assist with this, our answers come with step-by-step methods for fixing issues, clearly marked pictures, and quick ways to find the best answer for each question. So, even problems with numbers are much easier to solve.

The chapter is now more focused on real-world applications according to the 2025 NCERT curriculum update. It now has more real-world examples, like how light bends when it goes through eyeglasses, cameras, and telescopes. At the same time, extra theory has been cut down so that students may focus on understanding the concepts. Our Light: Reflection and Refraction NCERT Solutions follow this new format, which makes studying for tests easier and less stressful.

In the end, these methods assist students not only get better grades, but also learn how light affects their daily lives. Students get better at drawing ray diagrams, solving math problems, and explaining optical phenomena in clear, straightforward language by using our Light – Reflection and Refraction NCERT Solutions on a regular basis.

FAQs – Class 10 Science Chapter 9

Why do I get confused with sign conventions in ray diagrams?

This is a common issue! Our solutions provide a quick guide and examples for each mirror and lens case to help you memorize them easily.

How can I remember the mirror and lens formulas for exams?

By practicing regularly with our stepwise problems, you’ll naturally learn when to apply each formula correctly.

What’s the easiest way to draw ray diagrams neatly?

Follow our guided diagrams that use clear labeling and standard notation—perfect for full marks in exams.

Are there real-life examples of reflection and refraction in these solutions?

Yes! Examples like mirrors, lenses, and eyeglasses help you connect textbook theory with real-world uses.

How can I improve my numerical solving speed for this chapter?

Our solutions include shortcuts, formula charts, and solved examples to help you solve faster and more accurately.